# Line slope calculator 4x+9y=49

**Straight line given by points A[1; 5] and B[10; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.4444x+5.4444

**Canonical form of the line equation:**4x+9y-49 = 0

**Parametric form of the line equation:**

x = 9t+1

y = -4t+5 ; t ∈ R

**Slope:**m = -0.4444

**Slope angle of line: φ =**-23°57'45″ = -0.4182 rad

**X intercept:**x

_{0}= 12.25

**Y intercept:**y

_{0}= q = 5.4444

**Distance line from the origin:**d

_{0}= 4.9752

**The length of the segment AB: |AB| =**9.8489

**Vector: AB =**(9; -4)

**Normal vector: n =**(4; 9)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**9x-4y-37.5 = 0

**Vector OA = (1; 5) ; |OA| = 5.099**

**Vector OB = (10; 1) ; |OB| = 10.0499**

**Scalar product OA .OB = 15**

**Angle ∠ AOB = 72°58'46″ = 1.2737 rad**